C 语言实例 - 计算两个时间段的差值

C 语言必背代码范例

计算两个时间段的差值。

实例

#include <stdio.h>
 
struct TIME
{
  int seconds;
  int minutes;
  int hours;
};
void differenceBetweenTimePeriod(struct TIME t1, struct TIME t2, struct TIME *diff);
 
int main()
{
    struct TIME startTime, stopTime, diff;
 
    printf("输入开始时间: \n");
    printf("输入小时、分钟、秒：");
    scanf("%d %d %d", &startTime.hours, &startTime.minutes, &startTime.seconds);
 
    printf("输入停止时间: \n");
    printf("输入小时、分钟、秒: ");
    scanf("%d %d %d", &stopTime.hours, &stopTime.minutes, &stopTime.seconds);
 
    // 计算差值
    differenceBetweenTimePeriod(startTime, stopTime, &diff);
 
    printf("\n差值: %d:%d:%d - ", startTime.hours, startTime.minutes, startTime.seconds);
    printf("%d:%d:%d ", stopTime.hours, stopTime.minutes, stopTime.seconds);
    printf("= %d:%d:%d\n", diff.hours, diff.minutes, diff.seconds);
 
    return 0;
}
 
void differenceBetweenTimePeriod(struct TIME start, struct TIME stop, struct TIME *diff)
{
    if(stop.seconds > start.seconds){
        --start.minutes;
        start.seconds += 60;
    }
 
    diff->seconds = start.seconds - stop.seconds;
    if(stop.minutes > start.minutes){
        --start.hours;
        start.minutes += 60;
    }
 
    diff->minutes = start.minutes - stop.minutes;
    diff->hours = start.hours - stop.hours;
}

输出结果为：

输入开始时间: 
输入小时、分钟、秒：12 34 55
输入停止时间: 
输入小时、分钟、秒: 8 12 5

差值: 12:34:55 - 8:12:5 = 4:22:50

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